20(y^2)=180

Solution for 20(y^2)=180 equation:

20(y^2)=180

We move all terms to the left:

20(y^2)-(180)=0

a = 20; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·20·(-180)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*20}=\frac{-120}{40}
=-3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*20}=\frac{120}{40}
=3
$